t^2/5-t^1/5-2=0

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Solution for t^2/5-t^1/5-2=0 equation: 


t in (-oo:+oo)

(t^2)/5-((t^1)/5)-2 = 0

(t^2)/5-(t/5)-2 = 0

1/5*t^2-1/5*t-2 = 0

DELTA = (-1/5)^2-(-2*1/5*4)

DELTA = 41/25

DELTA > 0

t = ((41/25)^(1/2)+1/5)/(1/5*2) or t = (1/5-(41/25)^(1/2))/(1/5*2)

t = 5/2*((41/25)^(1/2)+1/5) or t = 5/2*(1/5-(41/25)^(1/2))

t in { 5/2*(1/5-(41/25)^(1/2)), 5/2*((41/25)^(1/2)+1/5) }

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